# [time-nuts] Regulating a pendulum clock

Tue Aug 10 01:54:54 UTC 2010

```I screwed up by a factor of a million..

jimlux wrote:
> Bruce Griffiths wrote:
>> Advisable given the required mass will probably be in the 10-100 ton
>> range.
>>
>> Bruce
>>
>> J. L. Trantham, M. D. wrote:
>>> Personally, I would get out of the way.  : )
>>>
>>> Joe
>>>
> Wait a minute.. is it that big? or is it much, much bigger..
>
> Inverse square is involved.
>
> The moon's mass is 7.3E22 kg, and it's 400 km away  (eccentric 0.055)

400 E3 km away...

>
> Let's say our mass is 4 meters from the pendulum... that's a factor of
> 1e5, so the inverse square is 1e10.. 7.3E22 /1e10 = 7.3E12 kg
> required... A bit more than 100 tons..<grin>

7.3E6 kg..
>
> Call it 7E9 tonnes.  If it were water, a sphere about 1200 meters in

12 meters in diameter

> I'm assuming you'll be using something really really dense (depleted
> Uranium, perhaps.. very, very inexpensive in 80,000 pound lots) that
> will get you about 20 times denser.. get you down to a 400 meter radius
> sphere.
>
4 meters in diameter... starting to be feasible, eh?

>

```