[time-nuts] Regulating a pendulum clock
jimlux at earthlink.net
Tue Aug 10 01:54:54 UTC 2010
I screwed up by a factor of a million..
> Bruce Griffiths wrote:
>> Advisable given the required mass will probably be in the 10-100 ton
>> J. L. Trantham, M. D. wrote:
>>> Personally, I would get out of the way. : )
> Wait a minute.. is it that big? or is it much, much bigger..
> Inverse square is involved.
> The moon's mass is 7.3E22 kg, and it's 400 km away (eccentric 0.055)
400 E3 km away...
> Let's say our mass is 4 meters from the pendulum... that's a factor of
> 1e5, so the inverse square is 1e10.. 7.3E22 /1e10 = 7.3E12 kg
> required... A bit more than 100 tons..<grin>
> Call it 7E9 tonnes. If it were water, a sphere about 1200 meters in
7E3 tonnes.. not too bad
12 meters in diameter
> I'm assuming you'll be using something really really dense (depleted
> Uranium, perhaps.. very, very inexpensive in 80,000 pound lots) that
> will get you about 20 times denser.. get you down to a 400 meter radius
4 meters in diameter... starting to be feasible, eh?
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