[time-nuts] second step : I need a clarification
Dott. Alfredo Rosati
alfredorosati at alice.it
Sat Jan 9 01:44:16 UTC 2010
this is very clear explanation / 2E-11 * 10E9 = (2*10)E(-11 +
9) = 20E-2 = 2E-1 = 0.2 Hz_
thanks very much .
now the first step is clear .
assuming a timebase at 10MHz with a short term stability of 2E-11 the
10MHz should be near 10.000.000.000. +/- 2 . ( or better floating
inside +/- 2)
if this is correct I do not understand why driving my specrum analyzer
the result at 10GHz is a residual FM near 2 Hz .
driving the same analyzer with 10MHz OCXO I do not see residual FM ( or
is very little ) The spectrum analyzer is hp 8566b .
Is there a well know explanation or I I make some mistakes ?
( I have plotting result in gif format)
the ocxo is 10811 , the time base creating residual FM is LPRO-101 .
regards alfredo i5uxj
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