[time-nuts] Frequency error -> Parabolic Time Error?
Tom Van Baak
tvb at leapsecond.com
Sat Apr 9 18:40:45 EDT 2005
Yes, the curve is described by a quadratic formula,
same as any parabola. The time, T, (phase) of a
reference oscillator is given by:
T = t0 + f0 * t + 1/2 * df * t^2.
-- where t0 is the initial time offset (phase),
-- and f0 is the initial frequency offset,
-- and df is the frequency drift per unit time.
This can give rise to several different looking shapes
depending on the initial conditions.
/tvb
----- Original Message -----
From: "Brooke Clarke" <brooke at pacific.net>
To: "Discussion of precise time and frequency measurement"
<time-nuts at febo.com>
Sent: Saturday, April 09, 2005 15:18
Subject: [time-nuts] Frequency error -> Parabolic Time Error?
> Hi:
>
> Suppose that my reference oscillator is offset from 10.0 MHz by some
> small amount. If I plot the time interval between the reference
> oscillator and a GPS 1 PPS what will the plot look like over a long time
> period, a parabola?
>
> Have Fun,
>
> Brooke
>
> --
> w/Java http://www.PRC68.com
> w/o Java http://www.pacificsites.com/~brooke/PRC68COM.shtml
> http://www.precisionclock.com
>
>
>
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