[time-nuts] LPRO Heat Sink?
sgunsel at verizon.net
Wed Sep 23 16:27:29 UTC 2009
It seems to me that the heat sink is like having a hole in the bottom
of the bucket, just takes longer to fill. Added thermal mass would
keep the temperature more even. A radiator just dissipates heat, the
hotter thew object the more heat it will dissipate. The radiator
doesn't know if it is at the "right" temperature or just too
hot. The temperature regulator (thermostat to me) would be adjusted
to provide sufficient heat when required, to bring the temperature to
the top end of the hysteresis band, then stop. When the temperature
hits the lower bound, the heat turns on again, and so on.
My current furnace thermostat has about a 0.5 degree F band, my older
one was more like 3 degrees F to minimize cycling of the heat pump.
It does make a noticeable difference in comfort level. I think the
oscillator would be in the same boat, keep the temperature band as
narrrow as possible, and add thermal mass to minimize the
cycling. If it gets too hot, the temp controller should be adjusted
to avoid the overshoot.
At 11:54 AM 9/23/2009, you wrote:
>There is likely a heater and temperature regulator in the physics package.
>For the regulator to work, there must be a way to dissipate excess heat.
>Think of the thing as a bucket with water running into it. You cannot
>control the level in the bucket, if you cannot completely shut off the
>water flow, without having some way of emptying some water out of the
>bucket. Just as you need a water leak, you need a heat leak.
> > I'm new to this, but it sounded more like this is to be a thermal
> > mass to minimize temperature swings.
> > Why would you want to efficiently cool something that you are trying
> > to heat and maintain at a constant temperature?
> > just curious in Medina, OH
> > At 11:12 AM 9/23/2009, you wrote:
> >>At 10:51 AM 9/23/2009, J. Forster wrote...
> >>>Monsterously thick will NOT do it. All that does is increase the heat
> >>>capacity of the HS, not it's ultimate thermal resistance (W/deg).
> >>>You need surface area...
> >>You need both. A 10 m x 10 m piece of aluminum foil won't do much,
> >>either, despite having a very large surface area.
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