[time-nuts] Regulating a pendulum clock

jimlux jimlux at earthlink.net
Tue Aug 10 01:54:54 UTC 2010


I screwed up by a factor of a million..

jimlux wrote:
> Bruce Griffiths wrote:
>> Advisable given the required mass will probably be in the 10-100 ton 
>> range.
>>
>> Bruce
>>
>> J. L. Trantham, M. D. wrote:
>>> Personally, I would get out of the way.  : )
>>>
>>> Joe
>>>
> Wait a minute.. is it that big? or is it much, much bigger..
> 
> Inverse square is involved.
> 
> The moon's mass is 7.3E22 kg, and it's 400 km away  (eccentric 0.055)

400 E3 km away...

> 
> Let's say our mass is 4 meters from the pendulum... that's a factor of 
> 1e5, so the inverse square is 1e10.. 7.3E22 /1e10 = 7.3E12 kg 
> required... A bit more than 100 tons..<grin>

7.3E6 kg..
> 
> Call it 7E9 tonnes.  If it were water, a sphere about 1200 meters in 
> radius...

7E3 tonnes.. not too bad
12 meters in diameter

> I'm assuming you'll be using something really really dense (depleted 
> Uranium, perhaps.. very, very inexpensive in 80,000 pound lots) that 
> will get you about 20 times denser.. get you down to a 400 meter radius 
> sphere.
> 
4 meters in diameter... starting to be feasible, eh?

> 



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