[time-nuts] Advice on 10 MHz isolation/distribution
WarrenS
warrensjmail-one at yahoo.com
Fri Feb 19 18:34:32 UTC 2010
OR
could AC couple it into the load, so you are not wasting all that DC peak current.
IF you really want to reduce the gate load and its output current then
Use a 2 to one AC coupled divider.
Provides 200 Ohms AC load to the driver, 50 Ohms to the load, and could be driven with a single output gate.
Also provides a high pass filter to reduce some of that low freq PS noise, especially if the input is AC coupled correctly.
ws
***********
[time-nuts] Advice on 10 MHz isolation/distribution
Bob Camp lists at cq.nu
Fri Feb 19 17:30:04 UTC 2010
Previous message: [time-nuts] Advice on 10 MHz isolation/distribution
Messages sorted by: [ date ] [ thread ] [ subject ] [ author ]
Hi
Yup, that works.
A couple of *very* minor points:
-------------
My guess is that your output stage will be pulling a bit more than 15 ma.
This assumes you are running a 50 ohm load and a 50 ohm output impedance to
deliver 13 dbm (~ 2.5 V p-p).
More or less, 100 ohms from +5 to ground would be 50 ma half the time. The
stage likely will pull 25 or more ma. (Says Bob who hopefully hasn't done
any typos in the last minute or so).
You might also want to parallel two (or more) gates to get the output
current into the "safe" region.
--------
More information about the time-nuts
mailing list