[time-nuts] second step : I need a clarification

[Dott. Alfredo Rosati]

this is very clear explanation     /      2E-11 * 10E9 = (2*10)E(-11 + 
9) = 20E-2 = 2E-1  = 0.2 Hz_

thanks very much .
now the first step is clear .

assuming a timebase at 10MHz with a short term stability of  2E-11 the 
10MHz should be near 10.000.000.000. +/- 2 . ( or better floating  
inside +/- 2)

if this is correct I do not understand why driving my specrum analyzer 
the result at 10GHz is a residual FM near 2 Hz .
driving the same analyzer with 10MHz OCXO I do not see residual FM ( or 
is very little ) The spectrum analyzer is hp 8566b .
Is there a well know explanation or I I make some mistakes ?

( I have plotting result in gif format)

the ocxo is 10811 , the time base creating residual FM is LPRO-101 .

regards alfredo i5uxj