[time-nuts] Basic question regarding comparing two frequencies
EWKehren at aol.com
EWKehren at aol.com
Mon Jul 26 18:00:17 UTC 2010
Hi,
Bob since has explained how the 1.0001 MHz are generated. My Austron uses
a Xtal filter. If you want a scan of the circuit contact me direst. The
resulting 100 Hz out of the D F/F results in a high resolution representation.
1 Hz is equal to 1E 6. If you now count the 100Hz with a counter that has
a recipical mode like the 5345, 5335 or Racal Dana 1992 you easily get 1
E-12 resolution or better.
Bert
In a message dated 7/26/2010 10:35:53 A.M. Eastern Daylight Time,
pvince at theiet.org writes:
Sorry Bert, I don't follow the last part about the 100Hz - can you
explain further please? (and is that 100.00 or 100.01 Hz?)
Peter
On 26 July 2010 14:27, <EWKehren at aol.com> wrote:
> Hi,
> ten years ago not having a super counter I copied the input circuit of
> the Austron 2110 that using an XOR gate mixes 5 MHz with 500 Hz getting
> 5.0005 MHz. It is devided down to 1.0001 Mhz which in turn is mixed in
74 HC 74
> D F/F giving 100 Hz, that most counters are able to count at high
> resolution. Still use it today. May be a time-nuts project.
> Bert Kehren
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