[time-nuts] T.I. experimenting - newbie question

[Joseph Gray]

Hal,

Here are the results I got using your suggestion. The numbers may be a
bit different than last night as I'm not sure I'm using the same
cable.

A+, B+ = 18.9 ns
A-, B- = 19.4 ns

Obviously there is some difference in delay between the A and B
channels. Otherwise, the two numbers would have been identical -
correct?

If I take the average of the two readings, I get 19.05 ns, which is
more precise than the readings I'm taking. I'm rounding to the nearest
0.1 ns on the readings.

A+, B- = 5014.6 ns
A-, B+ = 5023.5 ns

If I take the average of these two readings and subtract out the 5 us
for 1/2 period of the 100 KHz square wave, if get 19.15 ns. This
agrees very closely with the above average.

I haven't looked at the service manual for the 5328A yet, so I don't
know if I even have the proper equipment to attempt a calibration. In
the mean time, would you say that taking the average of the first two
readings is a valid method?

Joe Gray
W5JG

On Sun, Apr 3, 2011 at 7:18 PM, Hal Murray <hmurray at megapathdsl.net> wrote:
>
> How about a square wave?  Start on one edge, stop on the next cycle.
>
> You can play with start on rising edge, stop on falling and the reverse.
> They should add up to the total.