[time-nuts] Q/noise of Earth as an oscillator
alex at pcscons.com
Thu Jul 28 00:43:15 EDT 2016
in case the Earth, the circular frequency of the Earth is equal of a
sinusoidal wave's frequency, which is a projection of the Earth circular
movement in a plain, which is perpendicular to the axis of the Earth.
The Q of the Earth in interpreted as the quotient of the phase speed of
the Earth's circular rotation [or the projected wave's] and the
fluctuation of the phase speed.
On 7/27/2016 8:10 PM, Neville Michie wrote:
> The discussion of Earth as a system with Q, but which is not resonant,
> is a more extreme case than the CONICAL PENDULUM.
> The conical pendulum has a simple form of a weight on a string, instead of oscillating
> in one plane as a conventional pendulum, it swings around in a circular orbit
> in the horizontal plane. It has a definite resonant frequency.
> Now a simple pendulum oscillates kinetic energy and potential energy, but a conical pendulum
> has constant potential energy and oscillates its energy from North-South energy to East-West
> I believe that a conical pendulum still has the circular error associated with amplitude.
> But will it be as good a time keeper as the simple pendulum?
> A curious fact about the conical pendulum is that whereas the simple pendulum has earth
> rotation forces that show in the Foucault Pendulum, the conical pendulum has a different
> period depending whether is swings clockwise or anticlockwise due to the earths rotation.
> What do you think?
> Neville Michie
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