[time-nuts] Divide by 3
alex at pcscons.com
Wed Jun 8 14:48:46 EDT 2016
utilizing rising and falling edges makes the circuit output signal duty
cycle sensitive to the input signal's duty cycle, and therefore the
harmonic content will vary with the input duty cycle variation.
On 6/8/2016 9:47 AM, Richard (Rick) Karlquist wrote:
> The URL you cited doesn't have the schematic in any obvious
> place. However, using both edges of the clock to supposedly
> result in 50% duty cycle output depends on having 50%
> duty cycle at the input. If you have differential logic
> like ECL, this can be realistic. Single ended logic,
> The other issue is that the divider can start up in any
> one of 3 phases with respect to any other frequency
> dividers in your system, unless you do something to
> synchronize the various dividers.
> This is probably old hat to most readers of time-nuts, but
> I just wanted to mention it in case some were unaware
> of it.
> On 6/8/2016 6:55 AM, Nick Sayer via time-nuts wrote:
>> I’m contemplating trying my GPS board with an FE-405B. That’s a
>> different kettle of fish, but at the end of that, if I’m successful,
>> one of the goals would be to be able to use it for the external
>> reference of my 53220A. Unfortunately, 15 MHz isn’t one of the
>> options - only 1, 5 and 10.
>> So I did some googling and found a divide-by-3 circuit using
>> flip-flops, and then designed a board for it:
>> The circuit uses 3 D flip-flops and 3 NOR gates and has a 50% duty
>> cycle output that’s 1/3 the frequency of the input. The OSHPark
>> project has a pointer to the original blog post that has a schematic.
>> The only difference between their schematic and mine is that in
>> theirs, the third flip-flop has an inverted clock input. The third
>> NOR gate inverts the clock to achieve that in mine (also one
>> flip-flop and one NOR gate are unused and have the inputs tied high).
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